Can anyone help me with the following:
I need to traverse subdirectories to create a list of files with the pathname. For example, here’s what I get with a simple ls –alR command:

/MAIN/data/30007390 dte2>>ls -alR

.:

total 2

drwxrwx--- 4 ecfadmin staff 96 Oct 24 18:35 .

drwxrwx--- 37 ecfadmin staff 1024 Oct 24 18:35 ..

drwxrwx--- 2 ecfadmin staff 96 Oct 24 18:35 GroupB

drwxrwx--- 2 ecfadmin staff 96 Oct 24 18:35 GroupA



./GroupB:

total 8

drwxrwx--- 2 ecfadmin staff 96 Oct 24 18:35 .

drwxrwx--- 4 ecfadmin staff 96 Oct 24 18:35 ..

-rwxrwx--- 1 ecfadmin staff 1968 Oct 24 18:35 02050506.GZ

-rwxrwx--- 1 ecfadmin staff 1976 Oct 24 18:35 02050720.GZ



./GroupA:

total 20

drwxrwx--- 2 ecfadmin staff 96 Oct 24 18:35 .

drwxrwx--- 4 ecfadmin staff 96 Oct 24 18:35 ..

-rwxrwx--- 1 ecfadmin staff 9453 Oct 24 18:35 05050602.GZ



What I would like to get back is something with the full path name and file name:



/MAIN/data/30007390/GroupB/02050720.GZ

/MAIN/data/30007390/GroupB/02050506.GZ

/MAIN/data/30007390/GroupA/05050602.GZ

*Permissions, primary and secondary group names, dates times and sizes are not needed but don’t have to be excluded.

I’m looking for something pretty straight forward, I could write a little shell to handle it but was hoping for something a little more elegant. (I was hoping there was a version (or option) of “ls” out there that might do it).

Any help would be appreciated.

try "find" instead ... see "man find" ...

find . -type f -print

That was exactly what I was looking for. It works great. Thanks very much!!!