How to get the days of Particular date?

Venkatesh1 · #1 01-23-2013

Quote:

Hi Am using unix Aix
I need to find out what days for a partciular date
if i give a DATE1 variable =01/01/2013

Code:

DATE1=01/01/2013

OUTPUT:
 Tue

Can anyone help me pls ..

Yoda · #2 01-23-2013

Refer thread

Venkatesh1 · #3 01-23-2013

Thanks for reply
I have seen the thread which you have mentioned
can you please explain briefly

Code:

 
d="20120103"

day=${d#??????}
temp=${d#????}
month=${temp%??}
year=${d%????}

Yoda · #4 01-23-2013

These are parameter substitution that you can perform in any POSIX shell.

Here is the definition from Korn Shell manual:

Code:

${parameter#pattern}
${parameter##pattern}
                               If the shell pattern matches the beginning of
                               the value of parameter, the value of this
                               substitution is the value of the parameter
                               with the matched portion deleted; otherwise
                               the value of this parameter substituted.  In
                               the former case, the smallest matching
                               pattern is deleted; in the latter case, the
                               largest matching pattern is deleted.
${parameter%pattern}
${parameter%%pattern}
                               If the shell pattern matches the end of the
                               value of parameter, the value of parameter
                               with the matched part is deleted; otherwise
                               substitute the value of parameter.  In the
                               former, the smallest matching pattern is
                               deleted; in the latter, the largest matching
                               pattern is deleted.

franzpizzo · #5 02-06-2013

It might be a good alternative: return 0 for Sunday, 1 for Monday etc.

Code:

echo "(6 - $( cal $MM $YY | awk 'NR==3' |wc -w ) + ( $DD % 7 ) ) %7" | bc

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