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| Thread | Thread Starter | Forum | Replies | Last Post |
| Sticky Bit???? | skyineyes | UNIX for Dummies Questions & Answers | 10 | 05-29-2008 10:15 AM |
| Sticky Bit | teenu18 | UNIX for Dummies Questions & Answers | 3 | 12-17-2007 11:08 AM |
| sticky bit | manu.vmr | Shell Programming and Scripting | 2 | 02-02-2007 03:43 AM |
| Sticky Bit | rob11g | UNIX for Dummies Questions & Answers | 1 | 03-14-2005 12:51 PM |
| Sticky bit | LivinFree | UNIX for Dummies Questions & Answers | 3 | 07-20-2001 08:28 PM |
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setuid sticky bit
I have a binary. It is having the following permissions
rws rws rwx mqm:mqm runmqtrm The same program on another machine is rws rws rwx root: mqm runmqtrm This program is a setuid program. This is what my understanding is. Whatever user the program is started under, it will finally be running as rmuser. Now if I start the program as root on the second one it starts ok. If I start the program as mqm on the first box it doesn't work. On the second box if I start it as root it works. Can somebody explain me this. Thanks |
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