Hi everyone,
I am receiving this error:
0403-057 Syntax error at line 6 : `}' is not expected.
when I try to enter in my function an if condition of the form:
#! /bin/ksh
do_t(){
var1="testing";recompr=0;
[[ $1 -eq 1 ]] && {printit=0;F_N_s="testing""."xx"."yy;}
}
do_t 1
###########

Am I not doing this right?
if I replace the if with the other format i.e.
if [[ $1 -eq 1 ]];then printit=0;F_N_s="testing""."xx"."yy;fi
it works fine
Please let me know.
Thanks!

[[ $1 -eq 1 ]] &&  printit=0 && F_N_s="testing""."xx"."yy

Hi.
Note the space after the opening curly brace... cheers, drl

Further to previous correspondents.

Should be

Hi.

As long as one obeys the syntax rules, many forms are possible:

#!/usr/bin/env ksh

# @(#) s1	Demonstrate syntax allowed for shell functions, ksh.

echo
export LC_ALL=C
echo "Environment: LC_ALL = $LC_ALL"
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version "=o" $(_eat $0 $1)
echo

one()
{
  echo " One called." >&2
  return 0
}

two(){
  echo " Two called." >&2
  return 0
}

three(){ echo " Three called." >&2 ; return 0
}

four(){ echo " Four called." >&2 ; return 0 ; }

echo
echo " Results, calling one, two, three, four."
one
two
three
four

exit 0

% ./s1

Environment: LC_ALL = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian GNU/Linux 5.0 
ksh 93s+


 Results, calling one, two, three, four.
 One called.
 Two called.
 Three called.
 Four called.