Hej Alla,

Jag behöver bara extrahera datum portion [*] från en apache loggfilen
Jag kan göra det med hjälp befälsordningen --

Loggfil innehåll - Första skivan --
\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d
197.130.211.240 - - [11/Mar/2009: 01:00:00 -0700] "GET / jp / index.shtml HTTP/1.1" 200 24255 "http://www.google.co.jp/search?q \u003d CCO & lr \u003d lang_ja & ie \u003d UTF-8 & oe \u003d
UTF-8 & aq \u003d t & RLS \u003d org.mozilla: jaofficiella & client \u003d firefox-a "" Mozilla/5.0 (Windows; U; Windows NT 5.1, ja, rv: 1.9.0.7) Gecko/2009021910 Firefox/3.0.7 "" C
TC \u003d 202.226.241.234.1211271614048643; SMIDENTITY \u003d 8dvPlQzpqd5 + avTXCpx7AWCRc3IbGqY7Mm6ECeAu/lwojS/RC4qmMwC + zQCHmNJekImecfJ9e8qJQVgI8Nb7hBe4rNRzPVXPRqUxTh69a
Bp4UA5oRd5SceTwPkA + RLB/ZvSST0Bvxk1dVnmo8R50VJ + IUDqB + N2854r7x/pihcXYObu7HLRFLdAhwVNYaamwWZ8qsTwgUEfUTZLlEGTlqsJuqo + DiO1nZnUmJ1PIgfIpEHeMpzxTiSpFI7FtTWYivH
GE9WeHfJBPV6EcuWONc9pvTfB4hprbm + sW5HxlzwP6wa2RdhpdO5rrLVX8DEP/I4fKYKTu0LYm0MIrVY1/xpNsHa3EkCgQL9F6r1Ns40qry9RRfCywEGhnDTk4jCsPCGF4s7bnwypVmpraunUq/jQLaBm
zLjB/Jr/uPcNR4zpodSuGbbc/8X3INPMx/LeXxAwau79aeBC40u7yGVZXYcyhdLJrsKOqwOcMcXJbOw9aW0SmQJrzCEtnEvc0nysGttJ5PwYdDO0Mrt5CIFs/IfTSKhDUB/Oa123IVoGO15TPHjE4XoFI
Jxk6FmNojzR1I2iSLgGKF4wwR44i9sPqXWwFfTUOUuRknOu614p368dorLg6gjhOdPvyX0apnP4RZA1iGR8f8FWuyDFQfvO3Mg2f QBoTQYIYSXBu372t8HNbvspnFElLuGqtHOyuC13a; USER_PROFIL
E \u003d eNpLTE5OLS72SS1LzbE1tgYAKM8FFg \u003d\u003d; __utma \u003d 152635051.1371569464997210600.1234262319.1234262319.1234865834.2; __utmz \u003d 152635051.1234262319.1.1.utmcsr \u003d (dire
ct) | utmccn \u003d (direkt) | utmcmd \u003d (none); s_pers \u003d% 20s_nr% 3D1236048421913% 7C1238640421913% 3B% 20gpv_p20% 3Dtools.cisco.com/search/jsp/search-results.get% 7C12367597
50363% 3B; s_sess \u003d% 20s_ria% 3Dflash% 252010% 257C% 3B% 20s_cc% 3Dtrue% 3B% 20s_sq% 3D% 3B "" 202.227.241.239 "

\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d
Hur jag försöker

dt \u003d "head -1 log-date-checker.txt | awk-F"] " '(print $ 1)' | awk-F" [ " '(print $ 2)' | cut-f1-d" ""

echo $ dt
\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d
Output

11/Mar/2009: 01:00:00


Vad behöver jag? --

\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d\u003d
Alla alternativ och en optimal lösning för att välja datum portion

Någon hjälp uppskattar

Tack