i cannot give array declaration in shell script

naree · #1 (**permalink**) 02-11-2008

Dear all,
i m unable to give array decalartion in solaris Operating system shell script

and script was so.sh

declare -a bull[90]

for i in 1 2 3 4 5 6 7 8 9
do

bull[$i]=$i
echo "${bull[$i]}"

done

it is throwing an error called

so.sh: declare: not found
so.sh: bull[1]=1: not found
so.sh: bad substitution

Sir if u cud help ragrding this issue

System Shock · #2 (**permalink**) 02-11-2008

For starters, "declare" means nothing to the shell.
If you are going to be using arrays, I'd suggest you switch to the korn shell, which I find more efficient in handling arrays than any other shell. In korn shell, you set an array with:

Code:

# set -A bull 1 2 3 4 5 6 7 8 9

This sets array "bull" with numbers 1 through 9 in spots 0 through 8, respectively.

fpmurphy · #3 (**permalink**) 02-11-2008

Actually "declare -a" is supported in the bash shell.

If the bash shell is available on your system, then the following should work (you may need to change "/usr/local/bin/bash" to point to wherever bash is installed on your system)

Code:

#!/usr/local/bin/bash

declare -a bull

for i in 1 2 3 4 5 6 7 8 9
do
    bull[$i]=$i
    echo "${bull[$i]}"
done

You can also perform the loop as follows

Code:

for  (( i=1; i < 10; i++ ))
do
    bull[$i]=$i
    echo "${bull[$i]}"
done

naree · #4 (**permalink**) 02-12-2008

Sir i m unable to do .. above mentioned in a script ..

It shooting same old error.

ara.sh: declare: not found
ara.sh: syntax error at line 3: `(' unexpected

ara.sh is

declare -a bull[10]

for (( i=1; i < 10; i++ ))
do
bull[$i]=$i
echo "${bull[$i]}"
done

fpmurphy · #5 (**permalink**) 02-12-2008

What shell are you using?

naree · #6 (**permalink**) 02-12-2008

Sir i m using BASH shell in solaris..

naree · #7 (**permalink**) 02-12-2008

Quote:

Originally Posted by fpmurphy

What shell are you using?

Sir i m using Bash Shell in which i m unable to work out this code..

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