I have a hard drive that we are trying to jumpstart in a sunblad 1500. we keep getting errors. I placed the drive in my 1500. I want to wipe the drive clean because for some reason it has a partition table. and when i go to format and try to format the drive it says it can not use a program. is there another way to wipe clean this secodary drive?

i tried
echo "PLEASE work" | dd of=/dev/dsk/c0t1d0s2 bs=1 count=512
and this did nto work at all either

corrupt label - label checksum
dada /pci@1e,6000000/ide@d/dad@1,0
corrupt label checksum failed

that is the error i am getting now after i re-ran the command that i posted

You should run 'format c0t1d0' and label the disk. Then take a look at the partition table and see what's left.

format c0t1d0s2 = cannot format this drive please use your manufactuer supplied formatting utility

then i choose the label option and i get
label= ready to label, continue?

if i press enter it repeats itself
i type yes it drops back to the format>

so not sure what to do

prtvtoc /dev/dsk/c0t1d0s2

Dimensions:
* 512 bytes/sector
* 255 sectors/track
* 16 tracks/cylinder
* 4080 sectors/cylinder
* 38309 cylinders
* 38307 accessible cylinders
*
* Flags:
* 1: unmountable
* 10: read-only
*
Partition 2
Tag 5
Flags 5
First Sector 01
Sector Count 156292560
Last Sector 156292559

* Directory

However

I hope you see the difference "c0t1d0" != "c0t1d0s2"