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Operating Systems Solaris Solaris 10
# 1  
Old 04-26-2016
Solaris 10
I am working on a Solaris 10 server that is quite locked down. When testing we want to add 15% more load to the CPU. We are unable to add stress or any program to do so. Does anyone have a way to do it where you can add lets say 10, 15, 20 percent load to cpu on top of this psrinfo -v gives me 175 virtual processors. psrinfo -pv gives me 4 physical processors
Code:
sparc-m5 32 virtual processors
sparc-m5 48 virtual processors
sparc-m5 48 virtual processors
sparc-m5 48 virtual processors

all clocking 3600MHz.
Last edited by DukeNuke2; 04-27-2016 at 03:28 AM..
# 2  
Old 04-26-2016
You can use this ksh/bash function:

Code:
# Usage: lc [number_of_virtual_cpus_to_load [number_of_seconds] ]
lc() {
  (
    pids=""
    cpus=${1:-1}
    seconds=${2:-60}
    echo loading $cpus CPUs for $seconds seconds
    trap 'for p in $pids; do kill $p; done' 0
    for ((i=0;i<cpus;i++)); do while : ; do : ; done & pids="$pids $!"; done
    sleep $seconds
  )
}

This User Gave Thanks to jlliagre For This Post:
Scrutinizer
# 3  
Old 04-26-2016
May I ask what the colon is for in front of the numbers? can I do 3600 seconds and 20 virtual cpu? can I save this as lc.sh?
# 4  
Old 04-26-2016
Quote:
Originally Posted by bdid
May I ask what the colon is for in front of the numbers?
That's the default values (one vCPU for 60 seconds)
Quote:
can I do 3600 seconds and 20 virtual cpu?
Sure, there is no hardcoded limit.
Quote:
can I save this as lc.sh?
Up to you. I'd rather save it in $HOME/Functions/lc and set FPATH=~/Functions (assuming ksh is used).
# 5  
Old 04-26-2016
I tried this as bash and it did not do anything. This is all I changed.
cpus=${27}
seconds=${60)
# 6  
Old 04-26-2016
There is nothing to change in the shell function I posted.

If you saved the function in lc.sh, run this:

Code:
. lc.sh
lc 27 60

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