sort the org_no & member_type column ascending

[durden_tyler]

Originally Posted by new2ksh

...
your code is

sort -k2,10 -k32,33

...

That isn't my code ! My code had 28, which you changed to 32 and expected it to work. Take a look at the series of responses above.

...
i want to see the record in alphabetical order like below
23333333330001695 000001039OLF-AA030600020091112
23333333330000060 000001039ODL-CH001000020091112
23333333330000111 000001039ODL-SP002000020091112

Can you please send me the right code both for the position 2:10 and 32:33
...

Since you haven't mentioned specifically, I shall assume that you want characters 2:10 sorted ascending and then characters 32:33 sorted ascending as well.

$
$ cat file1.dat
21111111110001343 000001004OLF-AA029100020091112
21111111110000060 000001004ODL-CH001000020091112
24444444440001416 000001045OLF-AA011800020091112
23333333330001695 000001039OLF-AA030600020091112
23333333330000111 000001039ODL-SP002000020091112
23333333330000060 000001039ODL-CH001000020091112
22222222220000780 000001013OLF-AA006500020091112
$
$ sort -k 1.2,1.10 -k 2.14,2.15 file1.dat
21111111110001343 000001004OLF-AA029100020091112
21111111110000060 000001004ODL-CH001000020091112
22222222220000780 000001013OLF-AA006500020091112
23333333330001695 000001039OLF-AA030600020091112
23333333330000060 000001039ODL-CH001000020091112
23333333330000111 000001039ODL-SP002000020091112
24444444440001416 000001045OLF-AA011800020091112
$
$