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how to read only the first two values from a file in unix
Hi,
I'm new to unix.. I need to read only the first two values from a file that contains many data....My record is like this FTG_ver_num=7.0 RUN_ID=2 $$tgt_envrnmt_cd=FTG $$WRK_FLW_CD=NPL I need oly the values of ETG_ver_num and RUN_ID. i.e) output to be 7.0 and 2 The code i used is: awk -F\:= '{print $1, $2}' filename |\ while read ETG_ver_num RUN_ID do echo "$ETG_ver_num" echo "$RUN_ID" done The Output i get is FTG_ver_num=7.0 RUN_ID=2 $$tgt_envrnmt_cd=FTG $$WRK_FLW_CD=NPL But i want only the first two.. kindly help me on this. |
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