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01-18-2009
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lines searching >>
hi guys! I`ll really appreciate your help. The situation is: i have a log file, and i need to get the needed lines from it. Code:
linecount=$(cat -n http.log | grep ALERT | awk '{print $1}' | wc -l)
lines=$(cat -n http.log | grep ALERT | awk '{print $1}')
1-string gets the number of found lines 2-string gets the string numbers What I need is to make script to get next 5 lines after each found $lines. For example: echo $lines 287 309 331 so the needed strings are 287-292, 309-314, 331-336. my idea was to make something like: Code:
cat -n http.log | grep ALERT | awk '{print $1}' > lines # to record needed string numbers in file
for i in $(seq 1 $linecount); do
let line$i=$(sed -n "$i" p lines) # to define each line number as variable :D i know that`s ugly
sed -n 'line$ip;line$i+1p;line$i+2p;...' http.log # that`s the ugliest ever, and that doesn`t work. Any suggestions?
done
it would be great if someone could show a quick solution of how to do that or just some suggestions! Thanks! Last edited by neverhood; 01-18-2009 at 04:34 AM.. |
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