Quote:

Originally Posted by ali560045 I have a script that will check for integer line by line and if it encounter any blank space will echo it: Below the script: Code: #!/bin/ksh while read i

If a line begins or ends with a space, that read command will strip it, and it will not be part of $i.

To capture leading and trailing spaces, set IFS to en empty string:

Code:

while IFS= read i

do
echo "Value is $i"

count=`expr substr "$i" 1 3`

In a POSIX shell, there is no need to use expr

Code:

temp=${i#???}
count=${i%"$temp"}

echo $count

if [ $count == 000 ] && [ "$i" != " " ]

The == operator is not standard; use =

The second test in unnecessary. If $count is 000, it cannot also be a space.

Better still, use a case statement:

Code:

case $i in
     000*) count=000;
esac

	
Quote:
	

	

		

			
				then
echo "Matched"
else
echo "Blank Space Found"
fi

done < a2.txt
			
		
	
	

Value is 0001650111
000
Matched
Value is

./a9.sh[9]: test: argument expected
Blank Space Found Value is 0001650111 000 Matched Value is ./a9.sh[9]: test: argument expected Blank Space Found

Quote:

Originally Posted by ali560045 still having the same problem not reading blank line.....below the script

You haven't tested for a blank line. You have tested for a line beginning with 3 spaces.