Print Selection of Line between two Identifiers.

parshant_bvcoe · #1 (**permalink**) 01-05-2009

I have a following containing DATA in the following format:

[START1]
DATA....------
---------------
--------------
[END1]
DATA.....------
--------------------
------------------
[START1]
DATA....------
---------------
--------------
[END1]

I want to extract the selective DATA in between identifiers [START1] and [END1] including starting identifier i.e, [START1] as depicted below:

[START1]
DATA....------
---------------
--------------
[START1]
DATA....------
---------------
--------------

Please help me with this.Thanks!

Ikon · #2 (**permalink**) 01-05-2009

Try this:

Code:

# cat somefile | awk -F '[START1]' 'BEGIN{RS="[END1]"; OFS="\n"; ORS=""} {print $2}'

summer_cherry · #3 (**permalink**) 01-06-2009

Code:

sed -n '/START1/,/END1/p' a.txt | sed '/END1/d'

Code:

awk '/START1/{flag=1}
/END1/{flag=0}
flag==1 {print}' a.txt

frostmourn · #4 (**permalink**) 01-06-2009

Code:

sed -n '/\[START1\]/{:a;N;/\[END1\]/!ba;s/\n[^\n]\+$//;p}' filename

parshant_bvcoe · #5 (**permalink**) 01-07-2009

Thanks Friends !!!

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