Count number of digits in a word

./hari.sh · #1 (**permalink**) 01-05-2009

Hi all

Can anybody suggest me, how to get the count of digits in a word

I tried

Code:

WORD=abcd1234
echo $WORD | grep -oE [[:digit:]] | wc -l
4

It works in bash command line, but not in scripts

tsurko · #2 (**permalink**) 01-05-2009

Could you show us how you use this code in your script? If you want to save it in a variable try something like this:

Code:

COUNT=`echo $WORD | grep -oE [[:digit:]] | wc -l`

./hari.sh · #3 (**permalink**) 01-05-2009

Let me tell you what exactly I want

I have a word having 8 chrs, something like abc12345 or ab123456

Now, if last five chrs are digits then I wanna do some other operation

I used the code

Code:


if [ `echo $WORD | cut -c 4-8  | grep -oE [[:digit:]] | wc -l` -eq 5 ]
then
do this...

bash command line it gives the output, but in script it gives "0" always"

SFNYC · #4 (**permalink**) 01-05-2009

Code:

$ cat ./testgrep.ksh
#!/bin/ksh

WORD=abc12345

echo $WORD|grep -qE "[[:digit:]]{5}$"
if [ $? -eq 0 ]; then
     echo "Do this with $WORD"
else
     echo "Else do this with $WORD"
fi

WORD2=ab123456

echo $WORD2|grep -qE "[[:digit:]]{5}$"
if [ $? -eq 0 ]; then
     echo "Do this with $WORD2"
else
     echo "Else do this with $WORD2"
fi

WORD3=abc1234

echo $WORD3|grep -qE "[[:digit:]]{5}$"
if [ $? -eq 0 ]; then
     echo "Do this with $WORD3"
else
     echo "Else do this with $WORD3"
fi

exit 0

$ ./testgrep.ksh
Do this with abc12345
Do this with ab123456
Else do this with abc1234

radoulov · #5 (**permalink**) 01-05-2009

Quote:

Originally Posted by ./hari.sh

Hi all

Can anybody suggest me, how to get the count of digits in a word

I tried

Code:

WORD=abcd1234
echo $WORD | grep -oE [[:digit:]] | wc -l
4

It works in bash command line, but not in scripts

It seems you're on GNU system, so you probably have bash >= 3 and you could try something like this:

Code:

$ WORD=abcd1234
$ [[ $WORD  =~ [0-9]{5}$ ]] && echo OK || echo KO
KO
$ WORD=abcd12345
$ [[ $WORD  =~ [0-9]{5}$ ]] && echo OK || echo KO
OK

vgersh99 · #6 (**permalink**) 01-05-2009

Code:

#!/bin/ksh

WORD=abcd1234

[[ $(echo "${WORD}" | awk '{print gsub("[0-9]", "")}')  -eq 5 ]] && echo OK || echo KO

radoulov · #7 (**permalink**) 01-05-2009

Or:

Code:

% perl -le'print shift=~/\d{5}$/?"OK":"KO"' abcd1234
KO
% perl -le'print shift=~/\d{5}$/?"OK":"KO"' abcd12345
OK

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
Count number of occurences of a word	shikhakaul	UNIX for Dummies Questions & Answers	8	06-25-2009 11:10 AM
PERL: Simple reg expr validate 6 digits number	BufferExploder	Shell Programming and Scripting	2	09-10-2008 11:15 AM
Count the number of occurence of perticular word from file	rinku	Shell Programming and Scripting	40	08-10-2007 07:33 PM
word count showing wrong number of lines	tselvanin	UNIX for Dummies Questions & Answers	3	01-06-2004 11:33 PM
restrain the number of digits of a PID	mlefebvr	UNIX for Advanced & Expert Users	1	05-27-2002 09:33 AM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes	Rate This Thread
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode	Rate This Thread: