Awk split doesn't work for empty delimiter

Orbix · #1 (**permalink**) 12-30-2008

Does anyone know how will I make awk's split work with empty or null separator/delimiter?

Code:

echo ABCD | awk '{ split($0,arr,""); print arr[1]; }'

I need output like:

HTML Code:

A
B
C
D

I am under HP-UX

Christoph Spohr · #2 (**permalink**) 12-30-2008

Hi,

try:

Code:

echo ABCD | awk '{ gsub(/./,"&\n",$0); print $0 }'

Output:

Code:

A
B
C
D

HTH Chris

Orbix · #3 (**permalink**) 12-30-2008

Sorry. I forgot to mentioned that I need to put each character in an array or variable, the reason I use the split function of awk.

Christoph Spohr · #4 (**permalink**) 12-30-2008

Code:

echo ABCD | awk '{ split($0,a,""); for (i in a){print a[i]} }'

Output:

Code:

D
A
B
C

pmm · #5 (**permalink**) 12-30-2008

To put in an array in awk-

echo ABCD | awk ' { for ( i = 1; i <= length($0); i++ ) a[i]=substr($0,i,1) } END { for ( i in a ) print a[i] } '

B
C
D
A

Orbix · #6 (**permalink**) 01-05-2009

Thanks a bunch! The code from pmm works but the one from Christoph Spohr did not. Im not sure why. Anyways, thanks again!

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