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12-09-2008
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How to find the actual process name
Dear All
I have created customisation appliaction for my application process which look likes below, 364688 ach_outbound -proc nla_acho_equ_01 -format EQUENS0001 [fat] DEQ WAIT 1167452 listener -p 42662 hostget_server -proc at_vld 11874 at_vld [fat] IDLE 1560634 listener -p 11870 menu [fat] IDLE 1843302 rate_server [fat] DEQ WAIT so now my concern is how can i fetch middle column between process id and [fat] i.e. my o/p shuould look like ach_outbound -proc nla_acho_equ_01 -format EQUENS0001 listener -p 42662 hostget_server -proc at_vld 11874 at_vld listener -p 11870 menu rate_server |
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12-09-2008
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One way:
Code:
root@isau02:/data/tmp/testfeld> cat bla 364688 ach_outbound -proc nla_acho_equ_01 -format EQUENS0001 [fat] DEQ WAIT 1167452 listener -p 42662 hostget_server -proc at_vld 11874 at_vld [fat] IDLE 1560634 listener -p 11870 menu [fat] IDLE 1843302 rate_server [fat] DEQ WAIT root@isau02:/data/tmp/testfeld> sed 's/^[0-9]* \([^\[]*\).*/\1/' bla ach_outbound -proc nla_acho_equ_01 -format EQUENS0001 listener -p 42662 hostget_server -proc at_vld 11874 at_vld listener -p 11870 menu rate_server |
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12-09-2008
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thank you so much.....it's working...fine..but can we right the same in awk...
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12-09-2008
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thank you so much for your support...i did it
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