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11-22-2002
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Running script using cron
I am running a script by scheduling it using the cron. The line in the cron file is -
10 * * * * ksh -v /apps/gofis/svam/cos_automation/cos_automation.sh vpqa > /apps/gofis/svam/cos_automation/cron.log 2>&1 But after the job is executed, the cron.log contains some part from cos_automation.sh script. Can some one help me. Thanks! AnkuR. |
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11-22-2002
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the -v option in ksh -v is sending a listing of your script to stderr (the 2> part of the command)
You have then redirected this to stdout (the > part) by putting 2>&1. To stop this happening either take out the -v option or redirect stderr to /dev/null. It depends whether you want to keep other errors or not. ie. do either 10 * * * * ksh /apps/gofis/svam/cos_automation/cos_automation.sh vpqa > /apps/gofis/svam/cos_automation/cron.log 2>&1 or 10 * * * * ksh -v /apps/gofis/svam/cos_automation/cos_automation.sh vpqa > /apps/gofis/svam/cos_automation/cron.log 2>/dev/null |
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11-22-2002
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guys, Thanks....it works well w/o "v" option.
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