Extra output in the script

himvat · #1 (**permalink**) 11-27-2008

Hi ,

I am trying to execute the following script.

#!/bin/sh
find . -name "common.log.diff"
if [$? -eq 1]; then
cp common.log common.log.diff
diff common.log common.log.diff > DIFFERENCE.log
cp common.log common.log.diff
grep "ERROR" DIFFERENCE.log
if [ $? -eq 0 ]; then
echo "1"
else
echo "0"
fi
else
diff common.log common.log.diff > DIFFERENCE.log
cp common.log common.log.diff
grep "ERROR" DIFFERENCE.log
if [ $? -eq 0 ]; then
echo "1"
else
echo "0"
fi
fi

This is giving the following output.

./testscript
./common.log.diff
./testscript[3]: [0: not found.
0

In this " 0 " is fine. But I dont know why it is
giving

./common.log.diff &
./testscript[3]: [0: not found.

along with "0"

Kindly suggest. What wrong with my script ?

Regards

zaxxon · #2 (**permalink**) 11-27-2008

Change

Quote:

if [$? -eq 1]; then

to

Code:

if [ $? -eq 1 ]; then

Also please use code tags.

himvat · #3 (**permalink**) 11-27-2008

let me check

himvat · #4 (**permalink**) 11-27-2008

No w it is giving the following output

./common.log.diff
0

what to do so that I dont get

./common.log.diff

I want only " 0 " as output

Kindly suggest

zaxxon · #5 (**permalink**) 11-27-2008

Code:

find . -name "common.log.diff" > /dev/null 2>&1

himvat · #6 (**permalink**) 11-27-2008

Yes !!!!!

It worked !!!

Thanks a Lot . U helped me a lot.

Regards

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