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11-11-2008
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Convert Epoch Time to Standard Date and Time & Vice Versa
Hi guys,
I know that this topic has been discuss numerous times, and I have search the net and this forum for it. However, non able to address the problem I faced so far. I am on Solaris Platform and unable to install additional packages like the GNU date and gawk to make use of their functions. Hence, I intend to go for Perl and include a one-liner command in the shell script for the conversion. As you can see below, I have no problem converting Epoch to Standard Date/Time. But for converting Standard Date/Time to Epoch, I am not getting the correct Epoch value. Am I missing anything here?  Convert Epoch to Standard Date/Time Code:
bash-3.00# perl -e 'print scalar(localtime(1226424300)), "\n"' Wed Nov 12 01:25:00 2008 Code:
bash-3.00# perl -e 'use Time::Local; print timelocal(0,25,1,11,11,2008), "\n";' 1228929900 bash-3.00# perl -e 'use Time::Local; print timegm(0,25,1,11,11,2008), "\n";' 1228958700 Thanks in advance. |
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11-12-2008
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works for me:
Code:
[yogeshs@helptoldreal-lr yogeshs]$ perl -e 'use Time::Local; print timelocal(0,25,1,11,11,2008), "\n";' 1228938900 [yogeshs@helptoldreal-lr yogeshs]$ perl -e 'print scalar(localtime(1228938900)), "\n"' Thu Dec 11 01:25:00 2008 [yogeshs@helptoldreal-lr yogeshs]$ |
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11-12-2008
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Quote:
Thanks for the reply. I found out that the month parameter for perl timelocal() need to "- 1". As in Jan to specify "0", Dec to specify 11. I got the value wrong, thats why epoch is not returning a consistent value. Code:
bash-3.00# perl -e 'print scalar(localtime(1226426701)), "\n"' Wed Nov 12 02:05:01 2008 bash-3.00# perl -e 'use Time::Local; print timelocal(1,5,2,12,10,2008), "\n"' 1226426701 |
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02-07-2009
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Quote:
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02-07-2009
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Not sure about perl but in bash:
# epoch $ date +%s # If you have a time already in mind you can change the line above to use YOUR time and not system time like this: date -d "Sat Feb 7 00:37:06 EST 2009" +%s # result = 1233985026 # and back to regular time from epoch date --date "Jan 1, 1970 00:00:00 +0000 + `date +%s` seconds" #You can substitute `date +%s` in the line above with your own epoch time that you have already obtained date --date "Jan 1, 1970 00:00:00 +0000 + 1233985026 seconds" # result = Sat Feb 7 00:37:06 EST 2009 Last edited by ddreggors; 02-07-2009 at 01:46 AM.. |
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