Sed to grep only numbers in string

ajilesh · #1 (**permalink**) 11-07-2008

Hi,

I would like to get only number in the following strings.

var1="Type20"
var2="type 3"
var3="value 2"
var4="Type 1 Datacenter Hall 2"

I would like to extract output as 20 from var1 and 3 from var2,2 from var3 and 1 from var4.

Appreciate any one help asap..

Regards,
Aji

joeyg · #2 (**permalink**) 11-07-2008

Code:

> echo "Type 20" | tr -d " " | tr -s "[:alpha:]" "~" | cut -d "~" -f2
20

> echo "Type 1 Datecenter Hall 2" | tr -d " " | tr -s "[:alpha:]" "~" | cut -d "~" -f2
1

chatwizrd · #3 (**permalink**) 11-07-2008

Nice use of the worm character :P

radoulov · #4 (**permalink**) 11-07-2008

Code:

$ cat file
var1="Type20"
var2="type 3"
var3="value 2"
var4="Type 1 Datacenter Hall 2"
$ sed 's [^"]*[^0-9]*\([0-9]*\).* \1 ' file
20
3
2
1

ajilesh · #5 (**permalink**) 11-07-2008

I have found out the solution my self and works fine..thanks for my self ..:P

nimbld1:root:/home/users/thayata/cvs/test # var="Type 3"
nimbld1:root:/home/users/thayata/cvs/test # print $var |tr -d '[A-Za-z]' |sed 's/ //g'
3
nimbld1:root:/home/users/thayata/cvs/test #

danmero · #6 (**permalink**) 11-07-2008

Quote:

Originally Posted by ajilesh

I have found out the solution my self and works fine..thanks for my self ..:P

What about var4 ? Your solution will return 12
Take radoulov solution.

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