taking a part from file name

Satyak · #1 (**permalink**) 10-29-2008

hi
i have a file with name "CT_Thread_Trace.384.20080728-121217.log"
i need 384 , can any one help

thanks
Satya

joeyg · #2 (**permalink**) 10-29-2008

> echo CT_Thread_Trace.384.20080728-121217.log | cut -d"." -f2
384
>

krishmaths · #3 (**permalink**) 10-29-2008

Code:

echo $filename | cut -d"." -f 2

Franklin52 · #4 (**permalink**) 10-29-2008

More possibilities:

Code:

echo 'CT_Thread_Trace.384.20080728-121217.log'| sed 's/[^.]*.\([^.]*\).*/\1/'

or:

Code:

echo 'CT_Thread_Trace.384.20080728-121217.log'| awk -F. '{print $2}'

Regards

ghostdog74 · #5 (**permalink**) 10-29-2008

Code:

# file="CT_Thread_Trace.384.20080728-121217.log"
# file=${file#*.}
# echo ${file%%.*}
384

cfajohnson · #6 (**permalink**) 10-29-2008

Quote:

Originally Posted by Satyak

hi
i have a file with name "CT_Thread_Trace.384.20080728-121217.log"
i need 384 , can any one help

Code:

file=CT_Thread_Trace.384.20080728-121217.log
IFS=.
set -- $file
echo $2

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