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10-29-2008
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getting the line number
hi
i have a file , that contains some data,i need to get the line numbr that cntains "Line timeout:" and thread no 3. i am using lineno1=$(awk '/'$THREADNO' Line timeout:/ {print NR}' $FILE) but the problem is if the thread no is 13, 23 , 43 it is taking that lines also,i need only that line that contains 3, Line timeout: please help thanks Satya |
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10-29-2008
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Post some lines of your input file and the desired output.
Regards |
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10-29-2008
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i/p file
20080729-115957.540859 [5521] D 3 Line timeout: 120 20080729-115957.540884 [5521] D 3 Start protocol: Wait SIGNON 20080729-115957.541100 [5521] D 3 Set timeout to: 120 ----------------------------------- ----------------------------- 20080729-115957.540859 [5521] D 13 Line timeout: 120 20080729-115957.540884 [5521] D 13 Start protocol: Wait SIGNON 20080729-115957.541100 [5521] D 13 Set timeout to: 120 o/p line number that contains only 3, Line timeout |
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10-29-2008
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if your string is say xyz
you can give command grep -n xyz filename which will show the line with the line number |
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