I need some help with the logic and syntax for a shell script (ksh) that will search a directory and look for similar files and save only the last two versions. The version number is in the file name. However, the files are of varying name lengths and may have 1 or many files, with no limit to the number of files. I am not sure that using the find command for date/timestamp is a good idea because these are adhoc files that get created.

For example:
Directory may have files like below

apps_V01.xml
betarelease_V01.xml
betarelease_V02.xml
betarelease_V03.xml
test_V01.xml
test_V02.xml
test_V03.xml
test_V04.xml
testing_V01.xml
testing_V(..).xml Representing all numbers 2 -99
testing_V100.xml

The result should be:
apps_V01.xml
betarelease_V02.xml
betarelease_V03.xml
test_V03.xml
test_V04.xml
testing_V99.xml
testing_V100.xml

I thought about putting the listing into a text file and then substringing the names using awk, but don't know how I would handle the number of similar files. My thought is to output the listing to a file, read the file until it reaches a new file creating an array of files and then save the last two in the array. Then read for the next set of files. But again, not sure how to do that. A problem also occurs when I only have 1 version of a file. I welcome any sed, awk or ksh commands. I don't know enough about Perl or any other language in order to do this. Some help would be greatly appreciated. I have searched more than 300 postings and not coming up with anything fairly close to what I need to accomplish.