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Is it possible with sed or awk?
Hi all, I am tring to write a script which should read the first line of the file and perform some task. Once the task is completed the next line of the file should be read the task should be performed. So is it possible to have a counter sort of thing, in sed or awk, which would increment and hence cause the next line to be read? Following is how I thought of doing it, but it does not work as I can't assign value to $C to get to read a line: Code:
C=1 #counter while true do LOG=`sed '$C!d' /var/log/somelog.log` # perform the task on $LOG # C=`expr $C + 1` done Thanks |
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Thanks for the reply danmero.
I had tried that earlier. When the script reads thru somelog.log and reaches EOF it exits. But I don't want it to exit. If the EOF is reached the script should wait till new line is added to somelog.log and then perform the task. Also the new to somelog.log would be added at random intervals. Any suggestions on how to have the script wait where it stopped rather than exiting and continue when the new line is added? Thanks. |
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Quote:
I haven't tried the alternative step yet as I am not familiar with logrotates. Would there be any other way to do this? Thanks. |
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Thanks for the reply tytalus.
I guess this would not work for me as my script contains 10 logics in it. So I took another route and using cron and ls and moving the files around once the job is over I got it to do the job. But it would have been nice and easier if I could just figure out a way to do this as I wanted. Still I will continue to read thru and see if I can do it the way I wanted to do it. Thanks again. |
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