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10-26-2008
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awk syntax doubt - trailing 1 value
In the below awk syntax, what does the value '1' signify?
awk '{....}1' file some eg: Code:
awk '{gsub(/[^[:cntrl:]]/,"")}1'
awk 'BEGIN{ORS=""}1'
awk '{ORS=(!(NR%5)?"":"\n")}1'
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10-26-2008
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awk evaluates the 1 as true and the prints the entire line by default, including a newline.
Code:
echo 'foo' | awk '/foo/{print}1'
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10-28-2008
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Quote:
Anyway, the default action of awk is to print the record right, even if the 'print' statement is missing? Last edited by royalibrahim; 10-28-2008 at 05:34 AM.. |
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10-28-2008
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Quote:
Code:
$ echo 'foo' | awk '/foo/' #default action
foo
$ echo 'foo' | awk '/foo/{print}' #defined action
foo
$ echo 'foo' | awk '/foo/{$1="bar"}' #defined action
$ echo 'foo' | awk '/foo/{print}1' #defined action and default action
foo
foo
$ echo 'foo' | awk '/foo/{$1="bar"}1'
bar
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10-29-2008
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Thanks danmero, I got the essence !! hat's off
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