I take the /etc/passwd file and print it out, but I only want the lines that end with sh.

I have
Which prints out all lines that have sh somewhere in it.

So I added $, which I thought matches the ends on lines, but its not working, like for example I have have file "sshd:x:100:65534::/var/run/sshd:/bin/false", that does not end in sh
Any suggestions?

Using cat with sed is redundant:

Regards

> cat /etc/passwd | egrep -v "sh$"

or, depending on your system

> cat /etc/passwd | grep -v "sh$"

or, using sed

> cat /etc/passwd | sed '/sh$/d'

@joeyg, multiple UUOC !

Yep, I knew that after I did the three examples. Late in the day, and just following the syntax lead of the OP (original post). Copied/pasted what person orignally tried, then modified slightly to fix and give correct results.

All of them could've been in format
command <file_in

For those who do not know - UUOC = useless use of cat. Don't use cat when you can redirect a file into stdin of a command. If that gets repeated thousands of times in a script it eats system resources - like inside a loop.