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10-23-2008
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Get zip path from unzip -l
I am listing the contents of a zip file and then grepping for a specific string ie: filename.a to get a line like: Code:
309753 10-18-08 15:20 etc/filename.a The etc/filename.a is the path the file is at within the zip file...how might I capture this path as I want to use that path to unzip that individual file from the archive without decompressing the entire archive. My problem is the path may vary such as 123-4565-A01/filename.a or may even just be something like anydirectoryname/filename.c Any suggestions would be greatly appreciated! Thanks. |
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