How can I perform a grep and it will give me a contain word (maintenance) instead of a string or the whole line of info.

grep with exclusive output?
or is there a CONTAIN with IF statement ?


I have a file call yast2_vhost.conf and it contain multiple entries call
maintenance.html
/srv/www/maintenance/
/srv/www/maintenance/maintenance.html ..etc


******************************************************
#!/bin/ksh
result=$(grep "maintenance" /etc/apache2/yast2_vhost.conf)

if [[ $result = maintenance ]]; then
echo "you messed up"
else
cp /etc/apache2/orginal.conf /etc/apache2/current.conf
fi

********************************************************

Several ways to do that. For example, have a look at "grep -c". Check the manpage if needed. It returns the number of matches found by grep. If you put that in a var, you can then check the var in your if statement.

$count = `grep -c bla /myfile`
if [[ $count -gt 0 ]]; then
...
fi

VIMES,

Thank you for your respond and ideas.

I looked at grep manpage and was able to find a flag that will work for my case. It is the -o

Thanks again.

Y