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10-16-2008
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Dynamic Log Deletion/Rotatoin Script
I've written a small static script for my log deletion, but I was wondering if there was a way to make it a dynamic script. here is how my script currently works.
Code:
#!/bin/sh
###########################################
#Script to zip logs older than 1 week old
#and to delete logs older than 30 days old
###########################################
#
##TEST
#
cd /opt/apache/test/logs
find . -name "access_*" -type f -mtime +8 -exec gzip {} \;
find . -name "access_*.gz" -type f -mtime +31 -exec rm {} \;
find . -name "error_*" -type f -mtime +8 -exec gzip {} \;
find . -name "error_*.gz" -type f -mtime +31 -exec rm {} \;
cd /opt/apache/test1/logs
find . -name "access_*" -type f -mtime +8 -exec gzip {} \;
find . -name "access_*.gz" -type f -mtime +31 -exec rm {} \;
find . -name "error_*" -type f -mtime +8 -exec gzip {} \;
find . -name "error_*.gz" -type f -mtime +31 -exec rm {} \;
cd /opt/apache/test2/logs
find . -name "access_*" -type f -mtime +8 -exec gzip {} \;
find . -name "access_*.gz" -type f -mtime +31 -exec rm {} \;
find . -name "error_*" -type f -mtime +8 -exec gzip {} \;
find . -name "error_*.gz" -type f -mtime +31 -exec rm {} \;
echo "Script complete on `date +%D`."
Possibly cd to /opt/apache/, do a listing, then somehow use an array and a loop to capture the name of each directory in to a variable, and then use that variable to run the find command, do those 4 lines, then if another directory exists repeat. |
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10-16-2008
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Hi, use:
Code:
find /opt/apache/test*/logs \( -name "access_*.gz" -o -name "error_*.gz" \) -type f -mtime +31 -exec rm {} \;
find /opt/apache/test*/logs \( -name "access_*" -o -name "error_*" \) -type f -mtime +8 -exec gzip {} \;
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10-16-2008
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Quote:
Code:
find /opt/apache/*/logs \( -name "access_*.gz" -o -name "error_*.gz" \) -type f -mtime +31 -exec rm {} \;
find /opt/apache/*/logs \( -name "access_*" -o -name "error_*" \) -type f -mtime +8 -exec gzip {} \;
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10-16-2008
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Of course!
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