extract/select pattern from input

TehOne · #1 (**permalink**) 10-14-2008

Hey,

examples of the input (text line):

/bla/blMOasdn234.adanif24/blabla.rar
/bla/blMOasdn234.adanif24/blabla23124.bin
/bla/bla/bla/bla/bla/bla.bin

and what I need to do is extract/select only the dir path so the output would be:

/bla/blMOasdn234.adanif24/
/bla/blMOasdn234.adanif24/
/bla/bla/bla/bla/bla/

I was trying to use sed and I could only get the oposite result, like

Code:

echo /test/test2/test3/noname.rar | sed 's/\/.*\///'

Franklin52 · #2 (**permalink**) 10-14-2008

Code:

sed 's_\(.*/\).*_\1_'

freelong · #3 (**permalink**) 10-14-2008

Code:

awk -F"/" '{for(i=1;i<NF;i++) {printf $i"/"} print ""}' filename

TehOne · #4 (**permalink**) 10-14-2008

Thank you, works fine!

summer_cherry · #5 (**permalink**) 10-15-2008

Code:

sed 's/\(.*\)\(\/.*\)/\1/' filename

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