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10-13-2008
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separate a line having particular field
hi
i have a file containes data like, 20081013-030618.675199 [2712] D 17 Change state DATA_RECEIVE->EOD, RC=0 20081013-030618.868358 [2712] D 17 Reading data... 20081013-030618.868498 [2712] D 18 Received 5 bytes 20081013-030618.868537 [2712] U Buffer received: now i need to cut the 4th field i.e 17 and write that line into a separate file please help thanks in advance Satya |
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10-13-2008
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Code:
awk '{print $4}' datafile > newfile
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10-13-2008
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Looks like sometimes that field doesn't appear. So you might want to augment it with: Code:
awk '$3 == "D" { print $4 }' datafile >newfile
And just pipe through "sort -u" so that you have only unique id's. |
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