how to print field n of line m

Deanne · #1 (**permalink**) 10-13-2008

Hi everyone, I have a basic csh/awk question.

How do I print a given field from a given line in a given file?

Thanks in advance!

Franklin52 · #2 (**permalink**) 10-13-2008

Code:

awk 'NR==given_line{print $given_field}' given_file

Regards

tayyabq8 · #3 (**permalink**) 10-13-2008

^^^^You missed the given field separator

Deanne · #4 (**permalink**) 10-13-2008

thanks franklin! will try it!

oh im using the default field separator (space)

Deanne · #5 (**permalink**) 01-14-2009

Hmmm, can someone help me why it doesnt work when i use a variable for the "given_line", eg:

awk 'NR==$counter{print $25}' $argv[1]

thanks in advance!

Franklin52 · #6 (**permalink**) 01-14-2009

Quote:

Originally Posted by Deanne

Hmmm, can someone help me why it doesnt work when i use a variable for the "given_line", eg:

awk 'NR==$counter{print $25}' $argv[1]

thanks in advance!

Try this:

Code:

 awk -v var=$counter 'NR==var{print $25}' $argv[1]

Regards

krishmaths · #7 (**permalink**) 01-14-2009

You need to use the -v option in awk to use shell variables, as below:

Code:

awk -v c=$counter 'NR==c {print $25}' $argv[1]

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