date addition

ali560045 · #1 (**permalink**) 10-13-2008

i have a script called date_add.sh written in k_shell

My shell script requirement is that it accepts a date from the user in the format YYYY-MM-DD and then it shows all the 15 days later day availaible in the current year

if date accepted from user is 2008-10-13,then the o/p sholud be
2008-10-28
2008-11-12
2008-11-27
2008-12-12
2008-12-27
-----------------------------------------------------------------------

How to put this logic in a loop? Also how to convert Epoch days into format YYYY-MM-DD

Current_day=`perl -e 'print int(time/86400);'`--------------------16145

but the below command is not working

perl -e '@d=localtime ((stat(shift))[9]); printf "%4d-%02d-%02d\n", $d[5]+1900,$d[4]+1,$d[3]' Current_day

ali560045 · #2 (**permalink**) 10-13-2008

below my script . Actually in my script i m taking the current date and then adding 15 days to it.
--------------------------------------------------------------------------

#!/bin/ksh

Current_day=`perl -e 'print int(time);'`
echo $Current_day

count=0
count=`expr $Current_day + 1296000`
echo $count

perl -le 'print scalar localtime('"$count"');'

perl -e '@d=localtime ((stat(shift))[9]); printf "%4d-%02d-%02d\n", $d[5]+1900,$d[4]+1,$d[3]' '"$count"'
--------------------------------------------------------------------------

the last command that converts the $count value into format YYYY-MM-DD is not working . plz help me in this?

jim mcnamara · #3 (**permalink**) 10-13-2008

stat works on files, not epoch seconds.

ali560045 · #4 (**permalink**) 10-13-2008

ok. so how to convert the value of the below command into the formay YYYY-MM-DD so i should get the o/p as 2008-10-28

perl -le 'print scalar localtime('"$count"');'

jim mcnamara · #5 (**permalink**) 10-13-2008

Code:

#!/bin/ksh
tictock()
{ 
perl -e '
 $now = time;
 $increment = 1296000;
    ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst) = localtime($now);
 $year += 1900;
 
 for($i=0, $thisyear = $year ; $thisyear==$year ; $i++)
 {
    printf ("%4d-%02d-%02d ", $year, $mon, $mday);
 	$incr=($increment * $i) + $now;
    ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)=localtime($incr);
    $year += 1900;
    $mon += 1;
  
 }
 '
}

set -A arr $(tictock )
let i=0
while [[ $i -lt ${#arr[*]} ]]
do 
    print ${arr[i]}
    i=$(( i + 1))
done

cfajohnson · #6 (**permalink**) 10-13-2008

Quote:

Originally Posted by ali560045

i have a script called date_add.sh written in k_shell

My shell script requirement is that it accepts a date from the user in the format YYYY-MM-DD and then it shows all the 15 days later day availaible in the current year

if date accepted from user is 2008-10-13,then the o/p sholud be
2008-10-28
2008-11-12
2008-11-27
2008-12-12
2008-12-27
-----------------------------------------------------------------------

Code:
. date-funcs
year=$( date +%Y )

_DATESHIFT=$1
while :
do
  _dateshift $_DATESHIFT 15
  [ ${_DATESHIFT%%-*} -ne $year ] && break
  printf "%s\n" "$_DATESHIFT"
done
The date-funcs library of shell functions is available at The Dating Game.

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