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10-11-2008
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Date function
I read man page for etc/shadow field..
on the 8th field, i assume that's the field to change account expire date. my question is: What value does the 8th field keep? i assume it's 13514 instead of "Date" value such as 11/10/08. on the man page, it said: " expire value = 13514 = jan 1, 2007" How do you get 13514 ? Is there any calculation involves? |
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10-11-2008
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It did not say that. If it did it is wrong.
That field is the number of days AFTER Jan 1, 1970 that the account expires - becomes unusable. |
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10-11-2008
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You should read man date for your *NIX, this solution should work on Linux date (GNU coreutils) 5.97
Code:
dt=1/1/07 # For January 1, 2007 # dt=$(date "+%d/%m%y") # For current date var=$(($(date -d $dt "+%s") / 86400)) echo $var 13514 |
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10-11-2008
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i made some syntax modification which are:
#old=1/1/07 old=`date +%d%m%y` var="(`(date -u $old "+%s")`/ 86400)" echo $var but i have a problme with the third line.. when i read man page for date, it only supports usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff] i'm guessing i should use -u but i think it's wrong Last edited by c00kie88; 10-11-2008 at 07:53 AM.. |
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10-11-2008
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What OS? and where you perform the calculation?
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