sed - delete until char x

mcW · #1 (**permalink**) 10-08-2008

Hi,

I got a Textfile contains hundreds of lines like this:

PHP Code:


			
3 02 8293820 0 22 22

All I need is this:

PHP Code:


			
293820 0 22 22

So i decided to delete until the first '8' comes up. But how I can realize that?

Franklin52 · #2 (**permalink**) 10-08-2008

Use cut:

Code:

cut -c 7- file > newfile

Regards

mcW · #3 (**permalink**) 10-08-2008

The only pattern I can use is the _first_ 8. The lines differ in the number of whitespaces, chars before the first 8 etc.

zaxxon · #4 (**permalink**) 10-08-2008

If I got it right, you want to cut off all digits until the first "8" shows up, including itself?:

Code:

sed -n 's/[^8]*8//p'

mcW · #5 (**permalink**) 10-08-2008

Yes, thats right. Works perfect. Thanks a lot!

mcW · #6 (**permalink**) 10-17-2008

Quote:

Originally Posted by zaxxon

If I got it right, you want to cut off all digits until the first "8" shows up, including itself?:

Code:

sed -n 's/[^8]*8//p'

Now Ive a new problem. Cut off all chars until the first "$" shows up, inc itself.
I tested: sed -n 's/[^\$]*\$//p', but didnt work, what ive to do in this case?

thanks in advance

danmero · #7 (**permalink**) 10-17-2008

Code:

sed -n 's/[^$]*\$//p'

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