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10-03-2008
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stat command error!!
Hi All,
can anyone please rectify this problem for me... if i am using stat command in shell scripting it is throwing error that stat command was not found.. how can i replace stat command with other command in unix shell scripting to get the size of the directory... the below is the code for stat command.. size_dir=$(stat -c %s $1) #$1 has the directory name (e.g. /root/kamal) echo $size_dir please help me to over come error in this code... Thanks & advance kamal |
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10-03-2008
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try replacing this:
Code:
size_dir=$(stat -c %s $1) #$1 has the directory name (e.g. /root/kamal) Code:
size_dir=$(/usr/bin/stat -c %s $1) #$1 has the directory name (e.g. /root/kamal) |
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10-03-2008
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Quote:
i dont want to use the stat command i want to replace it with other command can u suggest some other code for simillar o/p .... thanks & regards kamal |
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10-03-2008
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if you have PHP
Code:
# size=`php5 -r '$a=stat("file");echo $a[7];'`
# echo $size
123
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10-06-2008
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or plain c
Code:
#include <stdio.h>
#include <sys/types.h>
#include <sys/stat.h>
int main(int argc, char *argv[])
{
struct stat filestats;
stat(argv[1],&filestats);
/*now print to print whaever you want
for example,
printf("%d\n",filestats.st_mtim.tv_sec);
*/
}
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