Need script to find errored files inside directories

osramos · #1 (**permalink**) 09-22-2008

Hi people.

I working on a script to check for files that they are suposed not to be on the directory. I mean, inside of each directory it must have some files but some could be wrong, and i want to move the files that are wrong.

Ex:
CSPOTGET edpst/CargadoresSPOT Historicos_Spot_MDI.zip
COBGET edpst/CargadorOmelBroker ??????.xls
CORGET edpst/CargadorOmelReuters CarOmlReuts.xls

On folder " edpst/CargadoresSPOT " must only have " Historicos_Spot_MDI.zip"

On folder " edpst/CargadorOmelBroker " must only have files with " yymmdd.xls" , and no others.

I imagine this "configuration" file where the 1st column is a variable, the second is the directory and the 3rd column is the file(s) of each directory.

Did you understand what i'm wrote?

osramos

jim mcnamara · #2 (**permalink**) 09-22-2008

You want to find files that DO NOT match the pattern, correct?
ksh allows you to do that:

Code:

#!/bin/ksh
# files that are not named Historicos_Spot_MDI.zip
ls edpst/CargadoresSPOT/!(Historicos_Spot_MDI.zip)
# 
ls edpst/CargadorOmelBroker/!(??????.xls)
#
ls edpst/CargadorOmelReuters/!(CarOmlReuts.xls)

osramos · #3 (**permalink**) 09-22-2008

Ok, it works.

But there are almost 50 directories, with some of them with 4 or 5 files to exclude ( not match ).

Can do this with a FOR cycle or something similar?

osramos

Quote:

Originally Posted by jim mcnamara

You want to find files that DO NOT match the pattern, correct?
ksh allows you to do that:

Code:

#!/bin/ksh
# files that are not named Historicos_Spot_MDI.zip
ls edpst/CargadoresSPOT/!(Historicos_Spot_MDI.zip)
# 
ls edpst/CargadorOmelBroker/!(??????.xls)
#
ls edpst/CargadorOmelReuters/!(CarOmlReuts.xls)

jim mcnamara · #4 (**permalink**) 09-22-2008

What you are asking is to create a resultset that all files minus pattern1 minus pattern2

The only problem for this is that we will have to use grep -v. The file matching patterns become regular expressions

Code:

??????.xls
# becomes regex:
[0-9]{6}\.xls

This will happen for every file you want to exclude. Otherwise, you cannot just

Code:

ls !(pattern)

for five different files because each instance of !(pattern2) will show other patterns like pattern2 pattern3... etc.

Code:

# generalized solution
ls directory | grep -v -e 'regex1' -e 'regex2' -e 'regex3'

Therefore you have to construct 50 different regexes (one for each file you have to specify) and apply some of them to the correct directory output from ls. I cannot do that for you.

osramos · #5 (**permalink**) 09-24-2008

Oh, i see.

Another problem i have, assuming i'm using " ls !(pattern) ", is the shell i'm using.

The server is a Windows Server but have installed CYGWIN and Bash doesn't recognize the " ! ".

Is there other solution?

Regards,

osramos

Quote:

Originally Posted by jim mcnamara

What you are asking is to create a resultset that all files minus pattern1 minus pattern2

The only problem for this is that we will have to use grep -v. The file matching patterns become regular expressions

Code:

??????.xls
# becomes regex:
[0-9]{6}\.xls

This will happen for every file you want to exclude. Otherwise, you cannot just

Code:

ls !(pattern)

for five different files because each instance of !(pattern2) will show other patterns like pattern2 pattern3... etc.

Code:

# generalized solution
ls directory | grep -v -e 'regex1' -e 'regex2' -e 'regex3'

Therefore you have to construct 50 different regexes (one for each file you have to specify) and apply some of them to the correct directory output from ls. I cannot do that for you.

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