How to perform arithmetic operation on date

agathaeleanor · #1 (**permalink**) 09-16-2008

Hi all,

I would appreciate if anyone knows how to perform adding to date.
As for normal date, i can easily plus with any number.
But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul.

Thanks in advance for your help.

subhendu81 · #2 (**permalink**) 09-17-2008

hi,

u can try the following...

expr `date +%d` + 3

subhendu

era · #3 (**permalink**) 09-17-2008

That specifically does not solve the problem of wrapping at end of month. The FAQ section has a good thread on date arithmetic; see that instead. Yesterdays Date/Date Arithmetic

dennis.jacob · #4 (**permalink**) 09-17-2008

Try:

Use date -d as shown below:

Quote:

date -d "$var days "
Wed Sep 24 00:30:27 IST 2008
var=60
date -d "$var days "
Mon Nov 17 00:30:37 IST 2008

vidyadhar85 · #5 (**permalink**) 09-17-2008

simply change TZ to change date..

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