i have some 350 files in a dir: i want to remove them in one shot,

ls -ltr | grep 'Sep 15' | head -350

the above command gives me those 350 files i need to remove them,how to implement remove logic here in this command?


i can get those 350 files using the above command only and therefore i want to implement the remove command there only.

plz help me in this

Hello,

Try this

find . -mtime -1 -exec rm -rf {} \;

-mtime -1 gives you the files for sep 16th i.e today..
find . -mtime -1 -print ---try this first.see if you get 350 files.if yes,
execute the above command on the prompt.Thanks

Alternatively:

ls -ltr | grep 'Sep 15' | head -350 | awk '{print $NF}' | xargs rm

ls -ltr | awk '/Sep 15/ && NR<=350 {print $NF}' | xargs rm

Thanks i got it . Thanks to all for their help.

One more thing i wanted to ask , i have a file which is tar and then gz

CurrentCollectorMeterReadBackup20080915.tar.gz

How to search for a file log1.txt inside the above file without uncompressing it. I mean to say how to do this

CurrentCollectorMeterReadBackup20080915.tar.gz | grep 'log1.txt '

You need to uncompress the data in order to examine it, although of course, you don't need to commit the uncompressed data anywhere.

zcat file.tar.gz | tar tf - log1.txt

i used the below command:It's giving error

zcat CurrentCollectorMeterReadBackup20080915.tar.gz | tar tf - CurrentCollectorMeterReadBackup_20081915051914684

Error:

CurrentCollectorMeterReadBackup20080915.tar.gz.Z: No such file or directory
tar: tape read error: unexpected EOF

Try gzcat instead.