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09-11-2008
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You are repeating yourself. Try to clarify what should happen.
The way I understand your question is: 1. Your file contains many lines, some of which are names of .gz files. Find those lines. 2. For each found line, unzip the file it names. 3. (Not clear what you mean; unzipping a file will replace it with an uncompressed version already; is that not what you want?) |
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09-12-2008
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hi,
you are absolutely right ....bt i wanna it in somethng different way.. let me clear you the question question with exzmple: lets say i have a file named "sample". it contains somany lines of data as /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample.gz /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample1.gz /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample2.gz ... ... i will take the file "sample" as input.after unzipping the output shud be output: ===== /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample1 /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample2 ... ... quick response is appreciable. |
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09-12-2008
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Code:
gunzip $(cat sample) |
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09-12-2008
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my requirement is:
input (lines in the file) /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample.gz /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample1.gz /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample2.gz ... ... output: ====== /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample1 /common/interface/inbound/na/data/pre-receive/gadtest/subhendu/sample2 ... ... i mean i want to replace all the line of the file by these new output lines. i.e (the line contain sample instead of sample.gz) Last edited by subhendu81; 09-12-2008 at 01:54 AM.. Reason: to remove the smileys |
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09-12-2008
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Oh, so you don't actually want to perform the gunzip, you just want to remove the .gzs from the file? Just use a sed search-and-replace (see man sed).
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09-12-2008
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Or if you want to unzip and echo out the resulting unzipped file name, try gzip -dv -- it will print a message for each file (albeit not in a very machine-readable form). Or perhaps try this:
Code:
sed -n 's/\.gz//p' file | tee outputfile | while read match; do gzip -d "$match".gz done |
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09-12-2008
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i wanna unzip that files as well as replace the files with .gz extn in main file with normal file(sample.gz to sample).
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