Folks

How best to read the last line of a file, to check for a particular value?

This is the last line of my file......

00000870000002000008 0000000020000

......I need to check that this line contains '70' in positions 7 and 8, before I continue processing.

Regards ... Dave

You can try the below and apply the condition according to the logic of your code :

x='00000870000002000008 0000000020000'
/home/ans >echo $x | awk '{ print substr($0,7,2); }'
70
/home/ans >echo ${x:6:2}
70

tmp=`sed '$!D' File Name | cut -c7-8`
if [ "$tmp" -eq "70" ]
then
<<process the file >>
else
echo "Skip it"
fi

if [ `tail -1 file | cut -c7-8` -eq "70" ] ; then echo "70 found"; fi

The same using awk only

if [ $(awk 'END{print substr($0,7,2)}' file) -eq "70" ] ; then echo "70 found"; fi

tail -1 file | egrep '^.{6}70' >/dev/null && echo Successamundo

I've coded as follows, as I don't know the name of my file (only the prefix), and also there may be mulitple files. I need to check all the files for '70' before I continue processing. I get the error at the bottom:

Code
=====
icofile=`ls -l /Invoices |grep DAAS | awk '{print $9}'`
if [[ $icofile != "" ]]
then
for files in $icofile
do
if [ `tail -1 $files | cut -c7-8` -eq "70" ]
then
echo "File correct format, has record 70..." >>$logfile
else
echo "File incorrect format, missing record 70..." >>$logfile
exit 2
fi
done
echo "Sending $icofile to Server" >>$logfile
else
echo "No files to send across..." >> $logfile
exit 3
fi

Error
=====
"./Transfer.DAAS[25]: test: 0403-004 Specify a parameter with this command."

(where line 25 is my check for '70')