Prase a file and stored the result to an array

youareapkman · #1 (**permalink**) 09-03-2008

Dear all ,

I have a file whose content has the following format:

jboss.web:type=ThreadPool,name=AAAA
jboss.web:type=ThreadPool,name=BBBB

How can I parse this file to get the value of the name of each line (AAAA , BBBB) and store the result to an array ? (array[0] = AAAA , array[1] = BBBB).
Different files will have different total number of lines.

Regards.

radoulov · #2 (**permalink**) 09-03-2008

What programming language you are using?

Franklin52 · #3 (**permalink**) 09-03-2008

You can do something like:

Code:

#!/bin/sh

cnt=0

awk -F"=" '{print$3}' file | while read name
do
  arr[$cnt]=$name
  let cnt=cnt+1
done

Regards

RahulJoshi · #4 (**permalink**) 09-03-2008

code:
sed -e 's/'^.*='/ /g' filename |awk '{print NR ,$1}'
or
sed -e 's/'^.*='/ /g' filename

this helps u. use in ur for loop

dennis.jacob · #5 (**permalink**) 09-03-2008

Try using the below in a loop to assign in an array:

Code:

sed 's/\(.*\)name=\(.*\)/\2/' file

or

Code:

while read line; do echo ${line#jboss.web:type=ThreadPool,name=}; done<file

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