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09-03-2008
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What's going wrong with sort?
Sort isn't behaving as I expect. Can someone tell me what's going on?
Incidentally, the infile was ordered by 'sort' previously. Why is 101m_lig1_frag1 before 101m_lig1_frag12 but after 101m_lig1_frag11? $infile... 101m_lig1_frag10 124 ... 101m_lig1_frag11 124 ... 101m_lig1_frag12 124 ... 101m_lig1_frag13 124 ... 101m_lig1_frag1 124 ... 101m_lig1_frag14 124 ... 101m_lig1_frag15 124 ... 101m_lig1_frag16 124 ... 101m_lig1_frag17 124 ... 101m_lig1_frag18 124 ... 100> sort $infile > $outfile $outfile 101m_lig1_frag10 124 ... 101m_lig1_frag11 124 ... 101m_lig1_frag1 124 ... 101m_lig1_frag12 124 ... 101m_lig1_frag13 124 ... 101m_lig1_frag14 124 ... 101m_lig1_frag15 124 ... 101m_lig1_frag16 124 ... 101m_lig1_frag17 124 ... 101m_lig1_frag18 124 ... |
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09-03-2008
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use sort -d infile..
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09-03-2008
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Thanks, but I'm still getting the same result... wierd!
daisy 1807>cat head.fps | awk '{print $1,$2,"..."}' | sort -d 101m_lig1_frag10 124 ... 101m_lig1_frag11 124 ... 101m_lig1_frag1 124 ... 101m_lig1_frag12 124 ... 101m_lig1_frag13 124 ... 101m_lig1_frag14 124 ... 101m_lig1_frag15 124 ... 101m_lig1_frag16 124 ... 101m_lig1_frag17 124 ... 101m_lig1_frag18 124 ... |
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09-03-2008
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sort -n
it may solv ur problem |
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09-03-2008
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You can give this a try:
Code:
awk '{print substr($1,15)" "$0}' infile | sort -n | cut -d" " -f2-
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09-03-2008
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Quote:
One option would be: Code:
for each in $(sed 's/101m_lig1_frag\(.*\) 124\(.*\)/\1/' infile | sort -n); do grep "^101m_lig1_frag$each " infile; done Quote:
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