How to fetch variable value in if block and to compare it with certain string

khushboo · #1 (**permalink**) 08-30-2008

Hi,

I am trying to execute this command

if [ `$exception_info | grep "Exception if any" > /dev/null 2>&1; echo $?` -eq 0 ]; then

but getting error .Some problem with reteriving the value of $exception_info.
Please help.Its urgent.

thanks

vidyadhar85 · #2 (**permalink**) 08-30-2008

try this..

Quote:

if [ `echo "$exception_info"|grep -w "Exception if any" > /dev/null 2>&1; echo $?` -eq 0 ]; then

khushboo · #3 (**permalink**) 08-30-2008

Its skipping this if block.

vidyadhar85 · #4 (**permalink**) 08-30-2008

Quote:

Originally Posted by khushboo

Its skipping this if block.

run your script as sh -x scriptname
then post the out put..

khushboo · #5 (**permalink**) 08-30-2008

hey thanks a lot.It worked ,i was not using double quote thts why i was getting the error.

thanks

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