To get previous or future dates based on input value

Sharmila_P · #1 (**permalink**) 08-07-2008

Hi,
I need something like,
if the input date is 24/Aug/2008 and the inputvalue is +8 then the result should be 1/Sep/2008 (8 days after the input date)
if the input date is 24/Aug/2008 and the inputvalue is -8 then the result should be 16/Aug/2008 (8 days before the input date)

is there any command in unix,using which i can get this.Please guide me.

Thanks.

fpmurphy · #2 (**permalink**) 08-07-2008

If you have the latest version of ksh93

Code:

$ printf "%(%e/%b/%Y)T\n"  "24/Aug/2008 8 days ago"
16/Aug/2008
$ printf "%(%e/%b/%Y)T\n"  "24/Aug/2008 8 days"
 1/Sep/2008
$

broli · #3 (**permalink**) 08-07-2008

the date comando can do this, if im not mistaken

Sharmila_P · #4 (**permalink**) 08-08-2008

Hi,

Its not helping as I don't have this version.
I tried something like this.
Code:
let noofdays=$1
let totaldays=24*noofdays
DATE_STAMP=`TZ=CST-$totaldays date +%d/%b/%Y `
echo "$DATE_STAMP"
Its working fine.but when I tried to replace the current date with the given input date I am getting some error.
Code:
let noofdays=$1
let inputdate=$2
let totaldays=24*noofdays
DATE_STAMP=`TZ=CST-$totaldays $inputdate `
echo "$DATE_STAMP"
input:
------
$1=2
$2=24/Jan/2008
error:
------
24/Jan/2008: No such file or directory
Why I am getting this error.how I can resolve this?any suggestion please..

fpmurphy · #5 (**permalink**) 08-08-2008

Because 24/Jan/2008 is the syntax for a file called 2008 which lives in a subdirectory called Jan which lives in a subdirectory called 24.

Sharmila_P · #6 (**permalink**) 08-08-2008

Please tell how i can resolve this issue?or is there any other way to get the result?

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