Hello,

I just want to know how If it's possiple to define 2 variable using foreach command ???

I have directory inside that directory around 1000 file, I want to rename all of this files to something I have it in a list. Example :-

------This is what in my directory----------
d1
d2
d3
d4
d5
------------------------------------------------------

I have a LIST which containe the new naming "more new_name" and I have this

omd1
omd2
omd3
omd4
omd5

I tried to do crazy way to done it :-

# ls mydirectory >> old_name
# foreach file (`more old_name`) file2 (`more new_name`)
mv $file $file2
end

I know this is crazy but I don't know how to do it

Please do help me

hi,
i would suggest a different approach.

list the names of all the files in a file

$ ls > outfile

now the file new_name is expected to contain 1000 names
so paste the two files

$paste outfile new_name > newfile

the newfile will contain

d1 omd1
d2 omd2
d3 omd3
... and so on

now open the file and prepend "mv" to the beginning of each line

$vi newfile

:%s/^/mv /g

don't forget the space
now save the file
and say
$sh newfile

and bingo...

hope it helps

asif

Asif,

:%s/^/mv /g

Here can u explain what %s signifies.. ^ denotes the beginning.. and what is this g for?? it denotes all the lines is it??

TIA,
Nisha

:%s/^/mv /g

this is a command mode operation of the vi editor.

open any file in the vi editor
press ESC once and type :

you will get this prompt on the bottom left of your screen

%s is for substitution.
^ is a special symbol which denotes the beginning of each line
"mv " please note there is a space after mv is the string to be substituted
and g is for replacing all the instances
g is of no use here as there will be only one beginning of the sentence in each line, but if there are multiple instances of the search string ( in this case "^"), the option g is used to replace all the instances. if not given, then only the first instance of the search string in each line will be replaced.

asif

sorry
i wrote more than what you asked.
didn't read your mail carefully

well from what your example says why dont you just do it this way.

#! /bin/ksh
cd (path to your directory here)
for i in `ls`; do
mv $i om$i
done

but then again. maby im not understanding your question.

%s is substitution across all rows in the file.

You could use '1,$ s' for the same (1 is first $ is last) - which is the same - but you also can do '1,10 s' which is rows 1 to 10.....etc.