SH: two variables in for loop - Page 3

pankajpw · #1 (**permalink**) 07-04-2009

I am not interested in any hijacking....was just need a help..

cfajohnson · #2 (**permalink**) 07-04-2009

Quote:

Originally Posted by pankajpw

I am not interested in any hijacking....was just need a help..

Then start a new thread (and explain the method that leads from your input to your desired output).

(And look at the paste command.)

rakeshawasthi · #3 (**permalink**) 06-30-2009

$#
it will give the no of parameters passed

kshji · #4 (**permalink**) 06-30-2009

One more, using set to array.

Code:

#!/usr/bin/ksh
set -A array1 $(cat list1)
set -A array2 $(cat list2)
n=${#array1[*]}
i=0
while (( i < n ))
do
     print "${array1[$i]} ${array2[$i]}"
    ((  i+=1  ))
done

vgersh99 · #5 (**permalink**) 06-30-2009

Quote:

Originally Posted by kshji

One more, using set to array.

Code:

#!/usr/bin/ksh
set -A array1 $(cat list1)
set -A array2 $(cat list2)
n=${#array1[*]}
i=0
while (( i < n ))
do
     print "${array1[$i]} ${array2[$i]}"
    ((  i+=1  ))
done

why exactly do you a 'cat'?
Use '<' for ksh/bash.

kshji · #6 (**permalink**) 06-30-2009

Yes in this case this is enough. My idea was more generally example, some commands give some list and use it.
set -A array1 $(<list1)
set -A array2 $(<list2)

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