Hello

I am a beginner of shell scripting and i am having trouble to do a for loop.

I want a for loop to do stuff 3 times.

i.e.

in visual basic i do this
for (counter = 0; counter < 3; counter++)

on my shell script i have something like this at the moment

server=/apps/scripts/server.txt
servercount=$(wc -l <$server) #It has 3 lines
for i in $servercount
do
Echo $i
done

When i run this shell script, it only shows me 3.. but i want it to show
1
2
3

I also tried

for (( j = 1 ; j <= 3; j++ ))
do
echo $j
done

but i got an error
test2.txt: line 4: syntax error near unexpected token `(('
test2.txt: line 4: `for ((i = 1;i<= 3;i++))'


done

do not use a for loop, you are reading multiple lines from the file.

This should get you started:

your code is basically:

I think your script ran fine because $servercount only contains one line entry.

sample code follows:

Hey guys

My script only shows the result "3" instead of "1" "2" "3" on each line.
and i know why it does not work because I used the wrong code at first.

I still don't know why the following code is not working for me... i got a syntax error

for (( j = 1 ; j <= 3; j++ ))
do
echo -n $j
done

Use While loop.

server=/apps/scripts/server.txt
servercount=`wc -l <$server`
typeset -i i=1
while [ $i -le $servercount ]
do
echo $i
(( i = $i + 1 ))
done

below added extra echo since the -n suppresses line feeds