How to get Previous date in this format.

Prat007 · #1 (**permalink**) 07-22-2008

hi ,

I am using this to get previous date :

#!/usr/bin/ksh
date '+%m %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
MONTH=`expr "$MONTH" - 1`
case "$MONTH" in
0)
MONTH=12
YEAR=`expr "$YEAR" - 1`
;;
esac
DAY=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
esac
echo "Yesterday was: $MONTH $DAY $YEAR"
}
Output : 07 21 2008

i want output as Jul 21, not as 07 21, can someone help me out.

Thanks

BMDan · #2 (**permalink**) 07-22-2008

How about:

Code:

$ date -d "yesterday" +"%b %d %Y"
Jul 21 2008

sudhamacs · #3 (**permalink**) 07-22-2008

YESTERDAY=`TZ=GMT+24 date "+%m %d %Y"`

fpmurphy · #4 (**permalink**) 07-22-2008

If you are using ksh93

Code:

$ printf "%(%b %d)T\n" "yesterday"
Jul 21
$

sujana · #5 (**permalink**) 07-23-2008

TZ=GMT+24 date "+%b %d %Y"

Jul 22 2008

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