Extracting data from a string containing &;

gugs · #1 (**permalink**) 07-18-2008

How can I exrtact the code HU52143N200401 from a string that contains &gt;HU52143N200401&lt;

zaxxon · #2 (**permalink**) 07-18-2008

One way:

Code:

sed 's/.*;.*;\([^&]*\)&.*/\1/g'

joeyg · #3 (**permalink**) 07-18-2008

Code:

> echo "&amp;gt;HU52143N200401&amp;lt;" | cut -d";" -f3 | cut -d"&" -f1
HU52143N200401

zaxxon · #4 (**permalink**) 07-18-2008

That's unfair! Mine was looking more complicated!

danmero · #5 (**permalink**) 07-18-2008

Code:

awk -F'[&|;]' '{print $4}'

radoulov · #6 (**permalink**) 07-18-2008

Well, in this case, with bash, zsh(with ^ instead of !) and ksh93:

Code:

% s='&amp;gt;HU52143N200401&amp;lt'
% printf "%s\n" "${s//[!A-Z0-9]}"
HU52143N200401

danmero · #7 (**permalink**) 07-18-2008

Or just tr

Code:

tr -d '[:punct:][a-z]'

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